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All rockets (chemical, electrical) generate thrust by throwing out particles at high velocity out their rear. Electric propulsion systems, such as Hall thrusters, use electricity (instead of chemical combustion) to create thrust.
All but the simplest EP systems operate by injecting neutral propellant and then
The difference in each EP is system is how they address these three points. For Hall effect thrusters (HETs):
This requires:
HETs have effectively 5 regions (some of which overlap):
of the ions are created in the production zone located in the region where the magnetic field starts to increase, i.e., about 1 cm from the exhaust. The neutral atom density drops by a factor of 10 or more in the production zone. [Boeuf1998]
Where does the plume fit into this? Also, where exactly are the neutralization and exhaust regions?
Two sources of current:
The discharge current is the sum of the ion beam current $I_b$ and the counter streaming electron current $I_e$.
Three sources of ions and electrons:
Confined electrons in the thruster ionize propellant which leads to a strong localized axial electric field which then accelerates the recently ionized ions for thrust.
Three motions of confined electron flow (add details, equations, etc)
Collisions - classic transport (add detail)
Anomalous transport (see below)
Roles of the cathode (Hollow cathode or HC)
Neglecting collisions, trapped electrons have three motions.
TODO - Create an idealized version of Fig. 8 in [Boeuf2017] to highlight (and maybe exaggerate) the three motions.
[Hoer2004] To optimize the efficiency of a Hall thruster it is critical to minimize the axial electron current by controlling the strength and shape of the magnetic field.
Classical (collisional) diffusion does not account for the observed electron current as the measured values are too large. This difference in diffusion is termed, “anomalous transport”.
[Boeuf2017] - has a good derivation. Maybe use it instead of Hofer's below.
[Hofer2004] - Derivation below
One dimensional steady-state electron motion is
$\nu_e n_e v_{ez} m_e + e n_e E_z + j_{e\theta}B_r + \nabla_z p_e = 0 $.
Including the relationship $\Omega_e = \frac{j_{e\theta}}{j_{ez}}$, the axial current can be solved
$j_{ez} = \mu_{ez} \left( -e n_e E_z - \nabla_z p_e \right)$
where
$\mu_{ez} = \frac{e}{\nu_e m_e} \left( \frac{1}{1+\Omega_e^2} \right) $
and the axial electric field ($E_z$) and pressure gradient ($\nabla_z p_e$) are the driving terms for the electron motion (current).
In regions where electrons are strongly magnetized, $\mu_{ez}$ simplifies to
$\mu_{ez} \approx \frac{e}{\nu_e m_e \Omega_e^2} = \frac{\nu_e m_e}{e Br^2}$
Classical collision frequency is around $10^6$ to $10^7$ $s^{-1}$ whereas measured effective collision frequencies is $10^7$ to $10^8$ $s^{-1}$, about an order of magnitude larger. This difference is termed “anomalous transport”. [Hofer2004]
The mechanisms responsible are likely from two sources : [Hofer2004]
Both mechanisms each play a role in different regions of the discharge chamber and at different thruster operating conditions. Mathematically, this can be accounted by including all three contributions (classical e-n collisions, wall interactions, and turbulence).
$\nu_e = \nu_{en} + \nu_{wall} + \nu_{turb}$.
$\nu_{ne}$ typically dominates $\nu_{ee}$ and $\nu_{ie}$, and therefore the two are typically ignored.
Several common low-frequency instabilities in HETs
[Choueiri2001]
[Fife1997]
[Choueiri2001]
[Me]
[Choueiri2001]
[Hofer2004]
[Choueiri2001]
[Choueiri2001]
[Choueiri2001]
TODO
[Hofer2004] Thruster performance is determined by the efficiency of the ionization and acceleration processes and is typically subdivided into three distinct processes:
Hofer then goes on to describe a forth, the charge utilization efficiency.
The net current flow is composed of ion (or beam) current to provide thrust and electron current that ionizes the propellant. The total discharge current is
$I_d = I_i + I_e. $
Ideally, you want to completely ionize the propellant with as little electron current as possible so that the ions (which have all the momentum and therefore provide the thrust) constitute the vast majority of the current. The (ion) current utilization efficiency is
$\eta_{beam} \equiv \frac{I_i}{I_e} $
As a practical matter, this efficiency will never reach 100% because some electron current is always needed.
The total mass flow from the anode consists of both ions and neutrals.
$\dot{m}_{anode} = \dot{m}_{i}+\dot{m}_{n} $
Ideally, the neutral propellant is 100% ionized. The mass-ionization efficiency is therefore
$ \eta_{mass-ionization} = \frac{\dot{m}_i}{\dot{m}_{anode}}$
and the true (density) ionization efficiency is $ \eta_{ionization} = \frac{n_i}{n_i + n_n}$
Note that they key distinction between the two is the velocity difference. Neutral particles have an average velocity around 0.4 km/s, and ions have an average velocity around 20 km/s.
Ideally, ions are accelerated over the full potential drop of the discharge voltage and are done so with no loss. However, this is completely true.
Thrust, from the POV of the thruster, is
$T = \frac{\partial}{\partial t} (m v) = \dot{m} v + m \dot{v}$
From the frame of reference on the thruster in steady-state operation, the thruster is not moving, the propellant has a constant mass flow rate $\dot{m}$ and a constant exhaust velocity $v$ when it leaves the thruster. Therefore, this equation reduces to
$T = \dot{m}_{prop} v_{exh}$
The total mass flow is split between
The cathode (mass) efficiency is defined as
$ \eta_c = \frac{\dot{m}_a}{\dot{m}_t} = \frac{1}{1+\frac{\dot{m}_c}{\dot{m}_a}} $
where the total mass flow is split between the anode $\dot{m}_a$ and the cathode $\dot{m}_c$ (the majority leaves at the anode).
$\dot{m}_{total}=\dot{m}_a+\dot{m}_c$
The total mass flow rate can then be expressed as
$\dot{m}_t = \dot{m}_a+\dot{m}_c = \frac{\dot{m}_a}{\eta_c}$
From the thrust equation earlier, the total effective exit velocity is
$c_t = \frac{T}{\dot{m}_t} = \frac{T}{\dot{m}_a}\eta_c$
Therefore, the total power of in the exhaust (jet) is
$P_{jet} = \frac{1}{2} T c_t $
However, this isn't particularly useful as we cannot measure $c_t$ an
The total thrust efficiency is the ratio of the kinetic power of the exhaust (which provides thrust) to the total electrical power input (i.e. how much “push” do we get per unit of energy input).
$ \eta_t = \frac{P_jet}{P_t} = \frac{\frac{1}{2} T c_t}{P_t} $
$ \frac{\frac{1}{2}T c_t }{P_t} = \ldots = \frac{T^2}{2 \dot{m}_a P_d} \eta_c \eta_{mag}$
And the total specific impulse is defined as
$I_{sp} \equiv \frac{T}{\dot{m}_t g} = \frac{T}{\dot{m}_a g}\eta_c = \frac{c_t}{g}$
Total power is the sum of the power to plasma discharge $P_d$, the magnetic field $P_{mag}$, and other auxiliary devices $P_{aux}$ such as the cathode keeper. $P_{aux}$ is typically zero in modern HETs.
$P_{tot} \approx P_{d} + P_{mag}$. $P_{mag}$ is typically 1% but can be as much as 4% depending on the design.
Electromagnetic efficiency is defined as
$\eta_{mag} \equiv \frac{P_d}{P_t} = \frac{1}{1 + \frac{P_{mag}}{P_d}}$
of Hall thruster design.
(Need citations…)
The goal of this section is to list common (or even uncommon) diagnostics associated with measuring “anything” in a Hall thruster.